Arithmetic daily test pyq

Percentage & Fraction Questions

Q1: Arun's present age is 40% of Barun's. After a few years, Arun will be half of Barun. Find % increase in Barun's age.

Let Arun = 4, Barun = 10. Later: Arun = 6, Barun = 12.
Increase = 2 → (2/10) × 100 = 20%

Q2: Ravi invests 50% in FDs, 30% of rest in stocks, rest in bank. FD + bank = 59,500. Find total savings.

FD = 10x, bank = 7x → 17x = 59,500 → x = 3500
Total = 20x = Rs 70,000

Q3: Girls appearing = 2 × boys. 30% girls & 45% boys qualify. Find % not admitted.

Let boys = 100 → girls = 200 → total = 300
Qualified: 45 + 60 = 105 → Not qualified = 195
% = (195/300) × 100 = 65%

Q4: 15% shirts defective. 20% of rest sold domestically. 8840 left for export. Total shirts?

Total = 100x → Defective = 15x → Rest = 85x
Domestic = 17x → Export = 68x = 8840 → x = 130
Total = 100x = 13,000

Q5: Food grain ↑ by 40%, per capita ↑ by 27%. Find % change in population.

% Increase = [(1.40 / 1.27) - 1] × 100 ≈ 10%

Q6: 68% of 4536 is less than N by 1%. Find possible value of N.

68% of 4536 = 3084.48
1% less → N = 3084.48 / 0.99 ≈ 3110.58

Q7: Meena scores 40%, later boosted 50% → 7 above pass. Reviewed ↑ 20%. Pass = 60a + 35. Find % of pass marks.

Let score after 50% boost = 60a → review adds 20% = 72a
60a + 35 + 7 = 72a → a = 3.5
Total = 100a = 350, Pass = 245
% = (245/350) × 100 = 70%

Q8: Amala earns 20% > Bimala. Kamala 50% > Amala. Kamala ↓ 4%, Bimala ↑ 10%. New % difference?

Bimala = 100 → Amala = 120 → Kamala = 150
New: Kamala = 144, Bimala = 110
% Difference = (144-110)/110 × 100 ≈ 31%

Q9: A's salary is 25% more than B's. What % is B's salary less than A's?

Let B = 100 → A = 125
Diff = 25 → % = (25/125) × 100 = 20%

Q10: Population ↓ 15% in year 1, ↑ 20% in year 2. Find net % change.

Using successive change: –15 + 20 – (15×20)/100 = 5 – 3 = 2% increase